# File Util/ranges.x # Modified April 9, 1997 by Doug Mink, Center for Astrophysics # Copyright(c) 1986 Association of Universities for Research in Astronomy Inc. include include define FIRST 0 # Default starting range define LAST MAX_INT # Default ending range define STEP 1 # Default step # DECODE_RANGES -- Parse a string containing a list of integer numbers or # ranges, delimited by either spaces or commas. Return as output a list # of ranges defining a list of numbers, and the count of list numbers. # Range limits must be positive nonnegative integers. ERR is returned as # the function value if a conversion error occurs. The list of ranges is # delimited by a single NULL. int procedure decode_ranges (range_string, ranges, max_ranges, nvalues) char range_string[ARB] # Range string to be decoded int ranges[3, max_ranges] # Range array int max_ranges # Maximum number of ranges int nvalues # The number of values in the ranges int i,ip, nrange, first, last, step, ctoi() begin ip = 1 nvalues = 0 # call printf ("DECODE_RANGES: string is %s\n") # call pargstr (range_string) do nrange = 1, max_ranges-1 { # Defaults to all positive integers first = FIRST last = LAST step = STEP # Skip delimiters to start of range while (IS_WHITE(range_string[ip]) || range_string[ip] == ',') ip = ip + 1 # Get first limit. # Must be a number, '-', 'x', or EOS. If not return ERR. if (range_string[ip] == EOS) { # end of list if (nrange == 1) { # Null string defaults ranges[1, 1] = first if (first < 1) ranges[2, 1] = first else ranges[2, 1] = last ranges[3, 1] = step ranges[3, 2] = NULL nvalues = nvalues + (abs (ranges[2,1]-ranges[1,1])/step) + 1 return (OK) } else { ranges[3, nrange] = NULL return (OK) } } else if (range_string[ip] == '-') ; else if (range_string[ip] == 'x') ; else if (IS_DIGIT(range_string[ip])) i = ctoi (range_string, ip, first) else return (ERR) # Skip delimiters while (IS_WHITE(range_string[ip]) || range_string[ip] == ',') ip = ip + 1 # call printf ("last: %d %s\n") # call pargi (ip) # call pargstr (range_string[ip]) # Get last limit # Must be '-', or 'x' otherwise last = first. if (range_string[ip] == 'x') ; else if (range_string[ip] == '-') { ip = ip + 1 while (IS_WHITE(range_string[ip]) || range_string[ip] == ',') ip = ip + 1 if (range_string[ip] == EOS) ; else if (IS_DIGIT(range_string[ip])) i = ctoi (range_string, ip, last) else if (range_string[ip] == 'x') ; else return (ERR) } else last = first # Skip delimiters while (IS_WHITE(range_string[ip]) || range_string[ip] == ',') ip = ip + 1 # Get step. # Must be 'x' or assume default step. if (range_string[ip] == 'x') { ip = ip + 1 while (IS_WHITE(range_string[ip]) || range_string[ip] == ',') ip = ip + 1 if (range_string[ip] == EOS) ; else if (IS_DIGIT(range_string[ip])) { if (ctoi (range_string, ip, step) == 0) ; } else if (range_string[ip] == '-') ; else return (ERR) } # Output the range triple. ranges[1, nrange] = first ranges[2, nrange] = last ranges[3, nrange] = step nvalues = nvalues + abs (last-first) / step + 1 # call printf ("DECODE_RANGES: %d %d %d %d %d\n") # call pargi (nrange) # call pargi (first) # call pargi (last) # call pargi (step) # call pargi (nvalues) } return (ERR) # ran out of space end # GET_NEXT_NUMBER -- Given a list of ranges and the current file number, # find and return the next file number. Selection is done in such a way # that list numbers are always returned in monotonically increasing order, # regardless of the order in which the ranges are given. Duplicate entries # are ignored. EOF is returned at the end of the list. int procedure get_next_number (ranges, number) int ranges[ARB] # Range array int number # Both input and output parameter int ip, first, last, step, next_number, remainder begin # If number+1 is anywhere in the list, that is the next number, # otherwise the next number is the smallest number in the list which # is greater than number+1. number = number + 1 next_number = MAX_INT for (ip=1; ranges[ip+2] != NULL; ip=ip+3) { first = min (ranges[ip], ranges[ip+1]) last = max (ranges[ip], ranges[ip+1]) step = ranges[ip+2] if (number >= first && number <= last) { remainder = mod (number - first, step) if (remainder == 0) return (number) if (number - remainder + step <= last) next_number = number - remainder + step } else if (first > number) next_number = min (next_number, first) } if (next_number == MAX_INT) return (EOF) else { number = next_number return (number) } end # GET_PREVIOUS_NUMBER -- Given a list of ranges and the current file number, # find and return the previous file number. Selection is done in such a way # that list numbers are always returned in monotonically decreasing order, # regardless of the order in which the ranges are given. Duplicate entries # are ignored. EOF is returned at the end of the list. int procedure get_previous_number (ranges, number) int ranges[ARB] # Range array int number # Both input and output parameter int ip, first, last, step, next_number, remainder begin # If number-1 is anywhere in the list, that is the previous number, # otherwise the previous number is the largest number in the list which # is less than number-1. number = number - 1 next_number = 0 for (ip=1; ranges[ip+2] != NULL; ip=ip+3) { first = min (ranges[ip], ranges[ip+1]) last = max (ranges[ip], ranges[ip+1]) step = ranges[ip+2] if (number >= first && number <= last) { remainder = mod (number - first, step) if (remainder == 0) return (number) if (number - remainder >= first) next_number = number - remainder } else if (last < number) { remainder = mod (last - first, step) if (remainder == 0) next_number = max (next_number, last) else if (last - remainder >= first) next_number = max (next_number, last - remainder) } } if (next_number == 0) return (EOF) else { number = next_number return (number) } end # IS_IN_RANGE -- Test number to see if it is in range. bool procedure is_in_range (ranges, number) int ranges[ARB] # Range array int number # Number to be tested against ranges int ip, first, last, step begin for (ip=1; ranges[ip+2] != NULL; ip=ip+3) { first = min (ranges[ip], ranges[ip+1]) last = max (ranges[ip], ranges[ip+1]) step = ranges[ip+2] if (number >= first && number <= last) if (mod (number - first, step) == 0) return (true) } return (false) end # May 22 1992 Allow first number in range to be zero # Apr 9 1997 If first is 0 and no last, last is also 0