C---------------------------------------------------------------------- subroutine ftgcxi(iunit,colnum,frow,nrow,fbit,nbit, & ivalue,status) C read any consecutive bits from an 'X' or 'B' column as an unsigned C n-bit integer, unless nbits=16 in which case the 16 bits C are interpreted as a 16-bit signed 2s complement word C iunit i fortran unit number C colnum i number of the column to read C frow i first row to read C nrow i number of rows to read C fbit i first bit within the row to read C nbit i number of bits to read C ivalue i*2 returned integer value(s) C status i output error status C C written by Wm Pence, HEASARC/GSFC, Nov 1994 C COMMON BLOCK DEFINITIONS:-------------------------------------------- integer nf,nb,ne parameter (nb = 20) parameter (nf = 3000) parameter (ne = 200) integer bufnum,chdu,hdutyp,maxhdu,hdstrt,hdend,nxthdr,dtstrt integer nxtfld logical wrmode common/ft0001/bufnum(199),chdu(nb),hdutyp(nb),maxhdu(nb), & wrmode(nb),hdstrt(nb,ne),hdend(nb),nxthdr(nb),dtstrt(nb),nxtfld integer tfield,tstart,tbcol,rowlen,tdtype,trept,tnull,scount integer theap,nxheap double precision tscale,tzero common/ft0002/tfield(nb),tstart(nb),tbcol(nf),rowlen(nb), & tdtype(nf),trept(nf),tscale(nf),tzero(nf),tnull(nf),scount(nb) & ,theap(nb),nxheap(nb) C END OF COMMON BLOCK DEFINITIONS----------------------------------- integer iunit,colnum,fbit,nbit,frow,nrow,status,i,j,k,row,ibuff integer*2 ivalue(*),ival,power2(16) logical lray(16) save power2 data power2/1,2,4,8,16,32,64,128,256,512,1024,2048,4096,8192, & 16384,0/ if (status .gt. 0)return ibuff=bufnum(iunit) if (nbit .gt. 16)then call ftpmsg('Cannot read more than 16 bits (ftgcxi)') status=308 return else if ((fbit+nbit+6)/8 .gt. trept(colnum+tstart(ibuff)))then call ftpmsg('Asked to read more bits than exist in'// & ' the column (ftgcxi)') status=308 return end if row=frow-1 do 30 k=1,nrow row=row+1 C get the individual bits call ftgcx(iunit,colnum,row,fbit,nbit,lray,status) if (status .gt. 0)return ival=0 j=0 if (nbit .eq. 16 .and. lray(1))then C interprete this as a 16 bit negative integer do 10 i=16,2,-1 j=j+1 if (.not. lray(i))ival=ival+power2(j) 10 continue C make 2's complement ivalue(k)=-ival-1 else C reconstruct the positive integer value do 20 i=nbit,1,-1 j=j+1 if (lray(i))ival=ival+power2(j) 20 continue ivalue(k)=ival end if 30 continue end