C-------------------------------------------------------------------------- subroutine ftmkys(ounit,keywrd,strval,comm,status) C modify a character string value header record C C ounit i fortran output unit number C keywrd c keyword name ( 8 characters, cols. 1- 8) C strval c keyword value C comm c keyword comment (47 characters, cols. 34-80) C OUTPUT PARAMETERS: C status i output error status (0 = ok) C C written by Wm Pence, HEASARC/GSFC, June 1991 C modifed 7/93 to support string keywords continued over multiple cards C modified 9/94 to support the OGIP long string convention character*(*) keywrd,strval,comm integer ounit,status integer clen,i,nvalue,ncomm character keynam*8,value*70,cmnt*48,bslash C-------COMMON BLOCK DEFINITIONS:-------------------------------------------- integer nb,ne parameter (nb = 20) parameter (ne = 200) integer bufnum,chdu,hdutyp,maxhdu,hdstrt,hdend,nxthdr,dtstrt integer nxtfld logical wrmode common/ft0001/bufnum(199),chdu(nb),hdutyp(nb),maxhdu(nb), & wrmode(nb),hdstrt(nb,ne),hdend(nb),nxthdr(nb),dtstrt(nb),nxtfld C-------END OF COMMON BLOCK DEFINITIONS----------------------------------- if (status .gt. 0)return C check if the new value is too long to fit in a single 'card image' clen=len(strval) if (clen .le. 68)go to 20 do 10 i=clen,69,-1 if (strval(i:i) .ne. ' ')go to 100 10 continue C now check that the old keyword is not continued over multiple cards C read the (first line) of the existing keyword 20 call ftgkey(ounit,keywrd,value,cmnt,status) if (status .gt. 0)go to 900 C is last character of the value a backslash or & ? C have to use 2 \\'s because the SUN compiler treats 1 \ as an escape bslash='\\' do 30 i=70,1,-1 if (value(i:i) .ne. ' '.and. value(i:i).ne.'''')then if (value(i:i) .eq. bslash .or. & value(i:i) .eq. '&')then C backspace the current header pointer by one record nxthdr(bufnum(ounit))=nxthdr(bufnum(ounit))-80 go to 100 else go to 40 end if end if 30 continue C OK, we can simply overwrite the old keyword with the new 40 continue C overwrite the old comment unless user supplied the magic value if (comm .ne. '&')then cmnt=comm end if C convert string to quoted character string (max length = 70 characters) call fts2c(strval,value,clen,status) if (status .gt. 0)go to 900 C find amount of space left for comment string C (assume 10 char. for 'keyword = ', and 3 between value and comment) C which leaves 67 spaces for the value string + comment string nvalue=max(20,clen) ncomm=67-nvalue C write the keyword record keynam=keywrd if (ncomm .gt. 0)then C there is space for a comment call ftmodr(ounit, & keynam//'= '//value(1:nvalue)//' / '//cmnt(1:ncomm),status) else C no room for a comment call ftmodr(ounit, & keynam//'= '//value(1:nvalue)//' ',status) end if go to 900 100 continue C Either the old or new keyword is continued over multiple C header card images, so have to use a less efficient way to modify C the keyword by completely deleting the old and inserting the new. C read the old comment, if we need to preserve it if (comm .eq. '&')then call ftgkys(ounit,keywrd,value,cmnt,status) if (status .gt. 0)go to 900 C reset the current header pointer by 2 records to make C it faster (usually) to find and delete the keyword nxthdr(bufnum(ounit))=nxthdr(bufnum(ounit))-160 else cmnt=comm end if C delete the old keyword call ftdkey(ounit,keywrd,status) if (status .gt. 0)go to 900 C insert the new keyword call ftikys(ounit,keywrd,strval,cmnt,status) 900 continue end