C-------------------------------------------------------------------------- subroutine ftrwdn(iunit,frow,lrow,nshift,status) C shift rows in a table down by NROWS rows, inserting blank rows C iunit i Fortran I/O unit number C frow i rows *AFTER* this one are to be moved down C lrow i last row to be moved down (last row of the table) C nshift i how far to shift the rows C status i returned error status (0=ok) integer iunit,frow,lrow,nshift,status C COMMON BLOCK DEFINITIONS:-------------------------------------------- integer nf,nb,ne parameter (nb = 20) parameter (nf = 3000) parameter (ne = 200) integer bufnum,chdu,hdutyp,maxhdu,hdstrt,hdend,nxthdr,dtstrt integer nxtfld logical wrmode common/ft0001/bufnum(199),chdu(nb),hdutyp(nb),maxhdu(nb), & wrmode(nb),hdstrt(nb,ne),hdend(nb),nxthdr(nb),dtstrt(nb),nxtfld integer tfield,tstart,tbcol,rowlen,tdtype,trept,tnull,scount integer theap,nxheap double precision tscale,tzero common/ft0002/tfield(nb),tstart(nb),tbcol(nf),rowlen(nb), & tdtype(nf),trept(nf),tscale(nf),tzero(nf),tnull(nf),scount(nb) & ,theap(nb),nxheap(nb) character*1 buff(2880,2) common/ftheap/buff C END OF COMMON BLOCK DEFINITIONS----------------------------------- integer ibuff,kshift,nchar,fchar,in,out,i,j,irow,tin,jrow integer lstptr,inptr,outptr,nseg character cfill*1 if (status .gt. 0)return C don't have to do anything if inserting blank rows at end of the table if (frow .eq. lrow)return C define the number of the buffer used for this file ibuff=bufnum(iunit) C select appropriate fill value if (hdutyp(ibuff) .eq. 1)then C fill header or ASCII table with space cfill=char(32) else C fill image or bintable data area with Null (0) cfill=char(0) end if C how many rows will fit in the single buffer? kshift=2880/rowlen(ibuff) C ********************************************************************** C CASE #1: optimal case where the NSHIFT number of rows will all C fit in the 2880-byte work buffer simultaneously. The rows can C be shifted down in one efficient pass through the table. C ********************************************************************** if (kshift .ge. nshift)then kshift=nshift nchar=kshift*rowlen(ibuff) fchar=1 C initialize the first buffer in=2 out=1 do 5 i=1,2880 buff(i,1)=cfill 5 continue do 10 irow=frow+1,lrow,kshift C read the row(s) to be shifted call ftgtbs(iunit,irow,fchar,nchar,buff(1,in),status) C overwrite these row(s) with the previous row(s) call ftptbs(iunit,irow,fchar,nchar,buff(1,out),status) C swap the input and output buffer pointers and move to next rows tin=in in=out out=tin jrow=irow 10 continue C write the last row(s) out irow=jrow+kshift nchar=(lrow-jrow+1)*rowlen(ibuff) call ftptbs(iunit,irow,fchar,nchar,buff(1,out),status) return C ********************************************************************** C CASE #2: One or more rows of the table will fit in the work buffer, C but cannot fit all NSHIFT rows in the buffer at once. Note that C since we do not need 2 buffers, as in the previous case, we can C combine both buffers into one single 2880*2 byte buffer, to handle C wider tables. This algorithm copies then moves blocks of contiguous C rows at one time, working upwards from the bottom of the table. C ********************************************************************** else if (rowlen(ibuff) .le. 5760)then C how many rows can we move at one time? kshift=5760/rowlen(ibuff) fchar=1 C initialize pointers lstptr=lrow inptr=lrow-kshift+1 20 if (inptr .le. frow)inptr=frow+1 nchar=(lstptr-inptr+1)*rowlen(ibuff) outptr=inptr+nshift C read the row(s) to be shifted call ftgtbs(iunit,inptr,fchar,nchar,buff,status) C write the row(s) to the new location call ftptbs(iunit,outptr,fchar,nchar,buff,status) C If there are more rows, update pointers and repeat if (inptr .gt. frow+1)then lstptr=lstptr-kshift inptr =inptr -kshift go to 20 end if C initialize the buffer with the fill value do 25 i=1,2880 buff(i,1)=cfill buff(i,2)=cfill 25 continue C fill the empty rows with blanks or nulls nchar=rowlen(ibuff) do 30 i=1,nshift outptr=frow+i call ftptbs(iunit,outptr,fchar,nchar,buff,status) 30 continue return C ********************************************************************** C CASE #3: Cannot fit a whole row into the work buffer, so have C to move each row in pieces. C ********************************************************************** else nseg=(rowlen(ibuff)+5759)/5760 nchar=5760 do 60 j=1,nseg fchar=(j-1)*5760+1 if (j .eq. nseg)nchar=rowlen(ibuff)-(nseg-1)*5760 do 40 i=lrow,frow+1,-1 C read the row to be shifted call ftgtbs(iunit,i,fchar,nchar,buff,status) C write the row(s) to the new location call ftptbs(iunit,i+nshift,fchar,nchar,buff,status) 40 continue C initialize the buffer with the fill value do 45 i=1,2880 buff(i,1)=cfill buff(i,2)=cfill 45 continue C fill the empty rows with blanks or nulls do 50 i=1,nshift outptr=frow+i call ftptbs(iunit,outptr,fchar,nchar,buff,status) 50 continue 60 continue end if end