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This section is just a reformulation of the original demonstration
by Ball (1976).
Let's assume that we are measuring
independent
on-positions for a single off. The same integration time (
) is spent
on each on-position and the off integration time is
 |
(53) |
where
can be varied. Using eq.
and
, it can be shown
than
 |
(54) |
Differenciating with respect to
, we obtain
 |
(55) |
Setting the result to zero then gives that
the minimum elapsed time to reach a given rms noise is obtained for
 |
(56) |
Gildas manager
2011-09-07